A) 0.2H
B) 0.1H
C) 0.8H
D) 0.4 H
Correct Answer: A
Solution :
Induced\[\text{e}\text{.m}\text{.f}\text{.e}\]\[=L\frac{{{\Delta }_{i}}}{\Delta t}\] \[8=L\times \frac{4-2}{0.05}\] \[L=0.2H\]
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