RAJASTHAN PMT Rajasthan - PMT Solved Paper-1999

  • question_answer
    \[2A+2B2C+2D\] For the above equation, the correct relationship is:

    A)  \[{{K}_{p}}={{K}_{c}}{{(RT)}^{-2}}\]

    B)                         \[{{K}_{p}}={{K}_{c}}\]

    C)                         \[{{K}_{p}}=\frac{{{K}_{c}}}{2}\]     

    D)                         \[{{K}_{p}}={{K}_{c}}{{(RT)}^{-1}}\]

    Correct Answer: B

    Solution :

    \[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta n}}\] \[\Delta n\] = number of mole (product) - number of mole (reactant) \[=4-4\] \[\Delta n=0\]                 \[\therefore \]  \[{{K}_{p}}={{K}_{c}}\]


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