A) Ammonium cyanide
B) Sodalime
C) Potassium cyanide
D) Sodamide
Correct Answer: A
Solution :
\[\underset{(inorganic)}{\mathop{N{{H}_{4}}CNO}}\,\xrightarrow{\text{Rearrangement}}\underset{(organic)\,Urea}{\mathop{N{{H}_{2}}-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,-N{{H}_{2}}}}\,\]
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