RAJASTHAN PMT Rajasthan - PMT Solved Paper-1999

  • question_answer
    When \[23g\]sodium metal reacts with methyl alcohol, it will form:

    A)   \[1mole\]of \[{{H}_{2}}\]   

    B)                         \[2\,mole\]of \[{{H}_{2}}\]

    C)                         \[\frac{1}{2}mole\]of \[{{H}_{2}}\]   

    D)                         all of these

    Correct Answer: C

    Solution :

    \[C{{H}_{3}}OH+Na\xrightarrow{{}}C{{H}_{3}}ONa+\frac{1}{2}{{H}_{2}}\] \[23g\,\,Na\] forms ?.\[\frac{1}{2}mole\] of


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