A) \[C{{l}^{-}}\]
B) \[O{{H}^{-}}\]
C) \[HCl\]
D) \[{{H}_{2}}O\]
Correct Answer: D
Solution :
\[{{H}_{2}}O\] is Bronsted acid and base both: \[\underset{Acid}{\mathop{{{H}_{2}}O}}\,+\underset{Base}{\mathop{{{H}_{2}}O}}\,\underset{Acid}{\mathop{{{H}_{3}}\overset{\oplus }{\mathop{O}}\,}}\,+\underset{Base}{\mathop{OH}}\,\]
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