A) \[{{10}^{11}}\]
B) \[{{10}^{16}}\]
C) \[{{10}^{19}}\]
D) \[{{10}^{15}}\]
Correct Answer: B
Solution :
\[\begin{align} & i=1.6\times {{10}^{-3}}A \\ & q=it\,\Rightarrow ne=it \\ \end{align}\] \[n=\frac{it}{e}=\frac{1.6\times {{10}^{-3}}\times 1}{1.6\times {{10}^{-19}}}\] number of electrons \[={{10}^{16}}\]
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