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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1999

  • question_answer
    For a triode valve \[\mu \,=\,50,\,\Delta \,{{V}_{g}}\,=0.2\] volt then value of\[\Delta \,{{V}_{P}}\,\] is:

    A)  5 volt                   

    B)         10 volt

    C)  0.2 volt               

    D)         50 volt

    Correct Answer: B

    Solution :

    Amplification factor                  \[\mu =\frac{\Delta {{V}_{p}}}{\Delta {{V}_{g}}}\] \[50=\frac{\Delta {{V}_{p}}}{0.2}\] \[\Delta {{V}_{p}}=10\,volt\]


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