A) \[\frac{mg}{r}\]
B) \[\sqrt{\frac{GM}{r}}\]
C) \[\sqrt{\frac{2GM}{r}}\]
D) \[\frac{GM}{r}\]
Correct Answer: B
Solution :
Orbital velocity \[{{\upsilon }_{o}}=\sqrt{\frac{GM}{r}}\] r = radius of circular path.
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