A) double
B) four times
C) half
D) remains same
Correct Answer: A
Solution :
Fringe width\[B=\frac{\lambda D}{d}\] D = distance between slits and screen. d = separation between slits. \[B'=\frac{\lambda D}{d/2}=2\left( \frac{\lambda D}{d} \right)\] fringe width becomes double.
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