A) 1200 year
B) 6400 year
C) 1800 year
D) 2200 year
Correct Answer: B
Solution :
Remaining quantity\[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] \[\frac{No}{16}=No{{\left( \frac{1}{2} \right)}^{n}}\] \[{{\left( \frac{1}{2} \right)}^{4}}={{\left( \frac{1}{2} \right)}^{n}}\] \[\therefore \] \[n=4\] \[\frac{t}{{{t}_{1/2}}}=4\] \[\Rightarrow \] \[t=4{{t}_{1/2}}\] \[=4\times 1600\,=6400\] year
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