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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1999

  • question_answer
    Three capacitors of 3, 2 and 6\[\mu F\] connected in series with a battery of 10V. Then charge on 3\[\mu F\] capacitor will be:

    A)  \[10\mu C\]      

    B)         \[12\mu C\]      

    C)         \[14\mu C\]      

    D)         \[5\mu C\]

    Correct Answer: A

    Solution :

    Equivalent capacity in series \[\frac{1}{C}=\frac{1}{3}+\frac{1}{2}+\frac{1}{6}\] \[C=1\mu F\] Charge of 1 \[\mu F\] capacitor \[q=CV\] \[=1\times 10\] \[=10\mu C\] (charge is same on all the capacitor in series combination)


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