A) with \[Na\] at \[413K\]
B) with cone. \[{{H}_{2}}S{{O}_{4}}\] at \[413K\]
C) with cone. \[HCl\] at \[413K\]
D) with \[B{{r}_{2}}\]at \[413K\]
Correct Answer: B
Solution :
\[\underset{\begin{smallmatrix} Ethyl\,alcohol \\ in\,excess \end{smallmatrix}}{\mathop{2{{C}_{2}}{{H}_{5}}OH}}\,\xrightarrow[{{140}^{o}}C\,\,or\,\,413K]{conc.\,{{H}_{2}}S{{O}_{4}}}\] \[\underset{Di\,\,ethyl\,\,ether}{\mathop{{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}+{{H}_{2}}O}}\,\]
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