A) \[M{{g}^{+2}}\]
B) \[B{{e}^{+2}}\]
C) \[N{{a}^{+}}\]
D) \[L{{i}^{+}}\]
Correct Answer: B
Solution :
\[B{{e}^{+2}}\] and \[M{{g}^{+2}}\] are smaller than \[L{{i}^{+}}\] and \[N{{a}^{+}}\] respectively. So \[B{{e}^{+2}}\] is the smallest ion.
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