A) \[C{{H}_{3}}OH\]
B) \[C{{H}_{3}}C{{H}_{2}}OH\]
C) \[\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,{{H}_{2}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,{{H}_{2}}\]
D) \[C{{H}_{3}}-\underset{\begin{smallmatrix} \,|| \\ O \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}\]
Correct Answer: C
Solution :
\[C{{H}_{2}}=C{{H}_{2}}+{{H}_{2}}O+[O]\xrightarrow[reagent]{Baeyers}\] \[\underset{Ethyledene\,glycol}{\mathop{\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,{{H}_{2}}-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,{{H}_{2}}}}\,\]
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