A) amino form
B) hexamethylene tetramine
C) urotropin
D) all of these
Correct Answer: D
Solution :
\[\underset{Formaldehyde}{\mathop{6HCHO}}\,+\underset{Ammonia}{\mathop{4N{{H}_{3}}}}\,\xrightarrow{{}}\] \[\underset{\begin{smallmatrix} \text{Hexamethyl}\,\text{tetramine} \\ \text{(Urotropin)} \end{smallmatrix}}{\mathop{{{(C{{H}_{2}})}_{6}}{{N}_{4}}}}\,+6{{H}_{2}}O\]
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