RAJASTHAN PMT Rajasthan - PMT Solved Paper-1998

  • question_answer
    The solubility product of chalk is \[9.3\times {{10}^{-8}}\]. What will be solubility of this?   

    A)  \[3.04\times {{10}^{-4}}mole/litre\]

    B)                         \[5\times {{10}^{-6}}\text{ }mole/litre\]

    C)                         \[3\times {{10}^{-5}}mole/litre\]

    D)                         None of these

    Correct Answer: A

    Solution :

    \[CaC{{O}_{3}}C{{a}^{++}}+CO_{3}^{--}\] \[Ksp={{s}^{2}}\] \[s=\sqrt{Ksp}\] \[=\sqrt{9.3\times {{10}^{-8}}}\] \[s=3.04\times {{10}^{-4}}mole/litre\]


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