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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1998

  • question_answer
    In bin bridge spectrograph the electric field is \[{{10}^{4}}\] volt/m and magnetic field is 1 T, then the velocity of undeflected positive ions is:

    A)  \[{{10}^{7}}\,m/s\]       

    B)         \[{{10}^{4}}\,m/s\]

    C)  \[{{10}^{5}}\,m/s\]        

    D)         \[{{10}^{2}}\,m/s\]

    Correct Answer: C

    Solution :

    \[V=\frac{E}{B}=\frac{V}{dB}=\frac{1000}{{{10}^{-2}}\times 1}\] \[={{10}^{5}}m/s\]


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