A) 3, 3
B) 3, 1
C) 5, 3
D) 3, 5
Correct Answer: B
Solution :
\[_{92}{{X}^{234}}{{\xrightarrow{{}}}_{82}}{{Y}^{222}}\] decrease in mass number \[=234-222\] \[\therefore \] Number of \[\alpha \] particles \[=\frac{12}{4}=3\] \[_{92}{{X}^{234}}{{\xrightarrow{-3\alpha }}_{86}}{{A}^{222}}{{\xrightarrow{{}}}_{87}}{{Y}^{222}}\] increase in atom number \[=87-86=1\] \[\therefore \] Number of \[\beta \] particles = 1 \[_{92}{{X}^{234}}{{\xrightarrow{{}}}_{87}}{{Y}^{222}}+3\alpha +1\beta \] Therefore, the number of \[\alpha \] and \[\beta \] particles is 3 and 1.
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