A) \[Pb(OH)Cl\]
B) \[BaCl\]
C) \[N{{a}_{2}}S{{O}_{4}}\]
D) \[N{{a}_{2}}HP{{O}_{4}}\]
Correct Answer: D
Solution :
Compound with acidic nature is\[N{{a}_{2}}HP{{O}_{4}}\].
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