A) \[_{\text{6}}{{\text{C}}^{\text{14}}}\,\text{and}{{\,}_{\text{6}}}{{\text{C}}^{\text{12}}}\]
B) \[_{\text{6}}{{\text{C}}^{\text{15}}}\,\text{and}{{\,}_{7}}{{\text{C}}^{\text{14}}}\]
C) \[_{7}{{\text{C}}^{\text{13}}}\,\text{and}{{\,}_{6}}{{\text{C}}^{\text{12}}}\]
D) \[_{7}{{\text{C}}^{\text{13}}}\,\text{and}{{\,}_{6}}{{\text{C}}^{\text{14}}}\]
Correct Answer: C
Solution :
\[_{7}{{N}^{13}}\] and \[_{6}{{C}^{12}}\] is pair of isotones because these have equal number of neutrons. Neutrons \[=13-7=12-6=6\]
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