A) one \[C{{l}^{-}}\] ion
B) two \[C{{l}^{-}}\] ion
C) any not \[C{{l}^{-}}\] ion
D) three \[C{{l}^{-}}\] ion
Correct Answer: C
Solution :
The co-ordination number of cobalt in complex \[CoC{{l}_{3}}.3N{{H}_{3}}\] is 6. thats why its formula is \[[Co{{(N{{H}_{3}})}_{3}}C{{l}_{3}}]\] because no any \[C{{l}^{-}}\] ion in ion area Thats why no any ion present in complex solution.
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