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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1996

  • question_answer
    On increasing the temperature of a gas filled in a close container by \[{{1}^{o}}C\], its pressure increases by 0.4%, initial temperature of the gas is:

    A)  \[{{25}^{o}}C\]                                                

    B)         \[{{250}^{o}}C\]                              

    C)         \[{{250}^{o}}K\]                              

    D)         \[{{2500}^{o}}C\]

    Correct Answer: C

    Solution :

    According to pressure law \[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\] \[\Rightarrow \]               \[\frac{P}{P+\frac{P\times 0.4}{100}}=\frac{x+273}{x+274}\]                 \[\frac{250}{251}=\frac{x+273}{x+274}\] \[\therefore \]  \[x=-{{23}^{o}}C=250K\]


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