A) \[5\]
B) \[50\]
C) \[57.5\]
D) \[75.5\]
Correct Answer: C
Solution :
Voltage gain \[A=\frac{{{\mu }_{{{r}_{L}}}}}{{{r}_{P}}+{{r}_{L}}}\] \[\mu =\frac{A({{r}_{P}}+{{r}_{L}})}{{{r}_{L}}}\] \[A=50,\,{{r}_{P}}=15k\Omega ,\,\,{{r}_{L}}=100k\Omega \] Substituting the values \[\mu =57.5\]
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