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  3. RAJASTHAN PMT

RAJASTHAN PMT Rajasthan - PMT Solved Paper-1996

  • question_answer
    A normally incident ray reflected at an angle of\[{{90}^{o}}\]. The value of critical angle is:

    A)  \[{{45}^{o}}\]                                   

    B)         \[{{90}^{o}}\]                   

    C)         \[{{65}^{o}}\]                                                   

    D)         \[{{43.5}^{o}}\]

    Correct Answer: B

    Solution :

    Critical angle C is equal to incident angle if ray reflected normally. \[\therefore \]  \[C={{90}^{o}}\]


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