RAJASTHAN PMT Rajasthan - PMT Solved Paper-1996

  • question_answer
    The peak value of an A.C. is \[2\sqrt{2}\] A, its rms value will be:

    A) \[\text{1A}\]                                     

    B)        \[\text{2A}\]                     

    C)        \[\text{4A}\]                                     

    D)         zero

    Correct Answer: B

    Solution :

    \[{{I}_{0}}=2\sqrt{2}amp\] \[{{I}_{rms}}=\frac{{{I}_{0}}}{\sqrt{2}}=2amp\]


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