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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1996

  • question_answer
    If the distance between a point source of light and a screen is made one third, then relation between intensity of light\[\text{(I)}\] and initial intensity \[\text{(}{{\text{I}}_{0}}\text{)}\]will be:

    A) \[\text{I=}\frac{{{\text{I}}_{\text{0}}}}{\text{3}}\]                                          

    B)        \[\text{I=}\frac{{{\text{I}}_{\text{0}}}}{9}\]                        

    C)        \[\text{I=}{{\text{I}}_{\text{0}}}\]                                          

    D)        \[\text{I=9}{{\text{I}}_{\text{0}}}\]

    Correct Answer: D

    Solution :

    Intensity   \[I\propto \frac{1}{{{r}^{2}}}\] If distance (r) is made one third, then intensity will become 9 times than the initial intensity.


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