A) \[C{{H}_{4}}\]
B) \[C{{H}_{3}}OH\]
C) \[C{{H}_{2}}=C{{H}_{2}}\]
D) \[C{{H}_{3}}CHO\]
Correct Answer: D
Solution :
\[2C{{H}_{3}}Cl+\underset{alcoholic}{\mathop{KOH}}\,\xrightarrow{\Delta }C{{H}_{2}}=C{{H}_{2}}+2KCl\] \[+2{{H}_{2}}O\]
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