A) \[i=5.4\,\sin \,(314t+\phi )\]
B) \[i=3.\,\sin \,(314t+\phi )\]
C) \[i=3.\,1\,\sin \,(314t-\phi )\]
D) \[i=3.\,46\,\sin \,(314t+\phi )\]
Correct Answer: B
Solution :
\[{{i}_{0}}=\frac{{{V}_{0}}}{Z}=\frac{314}{99.1}=3.1A\] \[\therefore \] \[i={{i}_{0}}\,\sin \,(\omega t+\phi )=3.1\,\sin \,(314t+\phi )\]
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