RAJASTHAN PMT Rajasthan - PMT Solved Paper-1995

  • question_answer
    In an L-C-R circuit C = 25 \[\mu F,\]L= 0.1 Hand R = 25 \[\Omega \] if an e.m.f. E = 310 sin 314 t volt is connected to circuit, then impedence is:

    A)  \[57.32\,\Omega \]                       

    B)                         \[79.48\,\Omega \]       

    C)         \[89.5\,\Omega \]                         

    D)         \[99.1\,\Omega \]

    Correct Answer: D

    Solution :

    Total impedence of L-C-R circuit \[Z=\sqrt{{{R}^{2}}+{{({{X}_{L}}-{{X}_{C}})}^{2}}}\] \[{{X}_{L}}=\omega L=2\pi \,fL\] \[{{X}_{L}}=\frac{1}{2\pi \,fC}\] \[f=50\] Substituting the values \[Z=99.1\Omega \]


You need to login to perform this action.
You will be redirected in 3 sec spinner