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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1995

  • question_answer
    In an electric dipole value of charge is \[3.2\times {{10}^{-19}}\] coulomb and distance between charges is \[2.4\,\overset{\text{o}}{\mathop{\text{A}}}\,\] It is placed in electric field of \[4\times {{10}^{5}}\,volt/m,\] then dipole moment of dipole is:

    A)  \[9.6\times {{10}^{-5}}\] coulomb-metre

    B)         \[12.8\times {{10}^{-14}}\] coulomb-metre

    C)         \[7.68\,\times {{10}^{-29}}\] coulomb-metre

    D)         \[30\times {{10}^{-24}}\] coulomb-metre

    Correct Answer: D

    Solution :

    Dipole moment of dipole \[\tau =P.\,E\] \[=q\times d\times E\] \[=3.2\times {{10}^{-19}}\times 2.4\times {{10}^{-10}}\times 4\times {{10}^{5}}\] \[=30\times {{10}^{-24}}\]coulomb metre


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