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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1995

  • question_answer
    The moment of inertia of a ring about its own axis is \[I.\] Then its moment of inertia, about a tangent in the plane is:

    A) \[\frac{I}{2}\]                                                    

    B)        \[\frac{3I}{2}\]                 

    C)        \[2I\]                                    

    D)                        \[\frac{5I}{2}\]

    Correct Answer: B

    Solution :

                    Moment of inertia of ring about its own axis \[I=M{{R}^{2}}\] M.I. about tangential axis \[I=\frac{3}{2}M{{R}^{2}}=\frac{3}{2}I\]


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