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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1995

  • question_answer
    In Youngs double slit experiment distance between slit is 0.1mm and distance between slit and screen is\[20cm\]. If \[\lambda =5460\,\overset{\text{o}}{\mathop{\text{A}}}\,,\], then fringe width is:

    A)  \[0.5mm\]                         

    B)                         \[1.1\text{ }mm\]                          

    C)         \[1.5\text{ }mm\]                          

    D)         \[2.2mm\]

    Correct Answer: B

    Solution :

    Fringe width \[\beta =\frac{\lambda D}{d}\] \[=\frac{5460\times {{10}^{-10}}\times 0.2}{0.1\times {{10}^{-3}}}\] \[=1.1\times {{10}^{-3}}m=1.1mm\]


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