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  3. RAJASTHAN PMT

RAJASTHAN PMT Rajasthan - PMT Solved Paper-1995

  • question_answer
    A second pendulum is suspended in satellite revolving round the earth a height 2R above earth surface, then its time period in second is:

    A)  zero                     

    B)         2 sec    

    C)         4 sec                    

    D)         infinite (\[\infty \])

    Correct Answer: D

    Solution :

    In a satellite \[g=0\] and \[T=2\pi \sqrt{\frac{l}{g}}\] \[\therefore \]  \[T=\infty \]


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