RAJASTHAN PMT Rajasthan - PMT Solved Paper-1995

  • question_answer
    Two sound sources \[{{S}_{1}}\] and \[{{S}_{2}}\] of frequencies \[324Hz\]and \[320Hz\] are placed at certain separation. An observer is moving on line joining them. If he hears no beats then speed of observer is: \[(\upsilon =344m/\sec )\]

    A)  \[20m/s\]        

    B)                        \[10m/s\]           

    C)         \[5m/s\]            

    D)         \[3.1m/s\]

    Correct Answer: D

    Solution :

    Number of beats \[\Delta n={{n}_{1}}-{{n}_{2}}\] For number beat \[\therefore \]   \[{{n}_{1}}-{{n}_{2}}=0\] \[\left( \frac{\upsilon +{{\upsilon }_{0}}}{\upsilon } \right)\times 324-\left( \frac{\upsilon -{{\upsilon }_{0}}}{\upsilon } \right)\times 320=0\] where, \[{{\upsilon }_{0}}\] = speed of observer,                 \[\upsilon =344\,m/s\] On solving \[{{\upsilon }_{0}}=3.1m/s\]


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