A) 6
B) \[\frac{15}{2}\]
C) 8
D) \[\frac{19}{2}\]
Correct Answer: B
Solution :
Since, two chords bisect each other, it means both the chords passes through the centre of circle. \[\therefore \]Length of chords are equal. i.e., \[{{a}^{2}}-1=3(a+1)\] \[\Rightarrow \] \[{{a}^{2}}-3a-4=0\] \[\Rightarrow \] \[(a-4)(a+1)=0\] \[\Rightarrow \] \[a=4\] (\[\because \]\[a=-1\]is not possible) \[\therefore \]Radius of circle \[=\frac{{{a}^{2}}-1}{2}=\frac{16-1}{2}=\frac{15}{2}\]
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