A) \[3,2,1,\frac{1}{2}\]
B) \[4,2,-1,\frac{1}{2}\]
C) \[4,1,0,-\frac{1}{2}\]
D) \[5,0,0,\frac{1}{2}\]
Correct Answer: B
Solution :
First find the orbitals from the given values of \[n\]and\[l,\]then find their energies according to \[(n+l)\] rule. [a] \[3,2,1,1/2\]means 3d (\[\because \]\[l=2\]means d ) [b] \[4,2,-1,1/2\]means 4d [c] \[4,1,0,-1/2\]means 4p (\[\because l=1\]means p) [d] \[5,0,0,1/2\]means 5s (\[\because l=0\]means s) \[n+l\]for\[3d=3+2=5\] \[n+l\]for\[4d=4+2=6\] \[n+l\]for \[4p=4+1=5\] \[n+l\]for\[5s=5+0=5\] \[\because \]Greater the value of\[n+l,\]more will be energy. \[\therefore \]\[4d\]orbital will have highest energy. \[4d>5s>4p>3d\]
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