A) \[{{C}^{2}}/N-{{m}^{2}}\]
B) \[{{C}^{2}}/{{(N-m)}^{2}}\]
C) \[N-{{m}^{2}}/{{C}^{2}}\]
D) \[C/N-m\]
Correct Answer: A
Solution :
We have, \[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\] \[\Rightarrow \] \[{{\varepsilon }_{0}}=\frac{1}{4\pi F}\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\] \[=\frac{(Coulomb)\times (Coulomb)}{Newton\times {{(Metre)}^{2}}}\] \[={{C}^{2}}/N-{{m}^{2}}\]
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