RAJASTHAN ­ PET Rajasthan PET Solved Paper-2011

  • question_answer
    In the binomial expansion of\[{{(a-b)}^{n}},n\ge 5,\] the sum of the 5th and 6th terms is zero, then a/b equals

    A)  \[\frac{n-5}{6}\]

    B)  \[\frac{n-4}{5}\]

    C)  \[\frac{5}{n-4}\]

    D)  \[\frac{6}{n-5}\]

    Correct Answer: B

    Solution :

     \[^{n}{{C}_{4}}{{a}^{n-4}}{{(-b)}^{4}}{{+}^{n}}{{C}_{5}}{{a}^{n-5}}{{(-b)}^{5}}=0\] \[\Rightarrow \] \[^{n}{{C}_{4}}a{{-}^{n}}{{C}_{5}}.b=0\] \[\Rightarrow \] \[a/b=\frac{^{n}{{C}_{5}}}{^{n}{{C}_{4}}}=\frac{n-4}{5}\]


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