A) \[AgI\]forms complex with \[NaI\]
B) of common ion effect
C) solubility product of\[AgI\]is less
D) the temperature of the solution decrease
Correct Answer: B
Solution :
The solubility of\[AgI\]in\[NaI\]solution is less than that in pure water because solubility is decreased due to common ion effect. \[AgIA{{g}^{+}}+{{I}^{-}}\] \[NaIN{{a}^{+}}+\underset{common\text{ }ion}{\mathop{{{I}^{-}}}}\,\]
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