A) 48 J
B) 32 J
C) 24 J
D) 288 J
Correct Answer: D
Solution :
Applying conservation of momentum \[{{m}_{1}}{{v}_{1}}={{m}_{2}}{{v}_{2}}\] \[{{v}_{1}}=8\times \frac{6}{4}=12\,m/s\] \[KE=\frac{1}{2}\times 4\times {{(12)}^{2}}=288\,J\]
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