A) 14.67 \[\mu \]F
B) 12.67 \[\mu \]F
C) 9.67 \[\mu \]F
D) 4.67 \[\mu \]F
Correct Answer: B
Solution :
\[f=\frac{1}{2\pi \sqrt{LC}}\] \[LC=\frac{1}{4{{\pi }^{2}}{{f}^{2}}}\] \[C=\frac{1}{4{{\pi }^{2}}L{{f}^{2}}}\] \[C=\frac{1}{4\times {{(3.14)}^{2}}\times 2\times {{10}^{-1}}\times {{(100)}^{2}}}\] \[C=\frac{5}{4\times {{(3.14)}^{2}}}\times {{10}^{-4}}F\] \[C=12.67\times {{10}^{-6}}F=12.67\mu F\]
You need to login to perform this action.
You will be redirected in
3 sec
