A) \[819{}^\circ C\]
B) \[719{}^\circ C\]
C) \[909{}^\circ C\]
D) None of these
Correct Answer: A
Solution :
\[{{c}_{rms}}\propto \sqrt{T}\] Or \[{{c}_{rms}}\propto \sqrt{273}\] ?.(i) Now consider that at temperature\[T',\]rms speed gets dubled, therefore \[2({{c}_{rms}})\propto \sqrt{T'}\] ... (ii) From Eqs. (i) and (ii), we get \[\sqrt{\frac{273}{T'}}=\frac{1}{2}\] \[\frac{273}{T'}=\frac{1}{4}\] \[T'=1092K=819{}^\circ C\]
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