A) 16 : 9
B) 4 : 3
C) 25 : 7
D) 49 : 1
Correct Answer: D
Solution :
Amplitude of superimposing waves are \[\left( \frac{{{a}_{1}}}{{{a}_{2}}} \right)={{\left( \frac{9}{16} \right)}^{1/2}}=\frac{3}{4}\] \[\frac{{{I}_{\max }}}{{{I}_{\min }}}=\frac{{{({{a}_{1}}+{{a}_{2}})}^{2}}}{({{a}_{1}}-{{a}_{2}})}\] \[=\frac{{{(3+4)}^{2}}}{{{(3-4)}^{2}}}=\frac{49}{1}\]
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