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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2011

  • question_answer
    A bullet of 5 g is fired with a velocity of 800 m/s. The velocity of bullet becomes 200 m/s when it pierces a wooden block 2 m thick. What is the average resistance offered by the wooden block?

    A)  8.5 kN          

    B)  7.5 kN

    C)  6.5 kN          

    D)  30 kN

    Correct Answer: B

    Solution :

     From work-energy theorem Work done by resistance of block = change in KE \[{{F}_{x}}=\frac{1}{2}m({{v}^{2}}-{{u}^{2}})\] \[F=\frac{0.05\times [{{(800)}^{2}}-{{(200)}^{2}}]}{2\times 2}\] \[F=7500N\] \[F=7.5kN\]


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