A) \[C{{H}_{2}}=CH-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{CH}}\,-COOH\]
B) \[C{{H}_{2}}=CH-\underset{\begin{smallmatrix} | \\ CN \end{smallmatrix}}{\mathop{CH}}\,-OH\]
C) \[C{{H}_{3}}C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{CH}}\,-COOH\]
D) \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{CH}}\,-COOH\]
Correct Answer: A
Solution :
\[C{{H}_{3}}CHO+HCHO\xrightarrow[\begin{smallmatrix} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\Delta \\ (aldol\text{ }condensation) \end{smallmatrix}]{Dil.\ NaOH}\] \[\underset{aldol}{\mathop{H-\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{2}}CHO}}\,\xrightarrow[{}]{\Delta }\underset{'A'}{\mathop{C{{H}_{2}}=CH-CHO}}\,\] \[\xrightarrow[{}]{HCN}C{{H}_{2}}\equiv CH-\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{C}}}\,-H\] \[\xrightarrow[{}]{{{H}_{3}}{{O}^{+}}}\underset{'B'}{\mathop{C{{H}_{2}}\equiv CH-\underset{\begin{smallmatrix} | \\ COOH \end{smallmatrix}}{\mathop{CH}}\,-OH}}\,\]
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