A) \[PbS\]
B) \[HCl\]
C) \[S{{O}_{2}}\]
D) \[Hg\]
Correct Answer: C
Solution :
The reaction of\[{{O}_{3}}\]with given compound are as [a] \[PbS+4{{O}_{3}}\xrightarrow[{}]{{}}PbS{{O}_{4}}+4{{O}_{2}}\] [b] \[2HCl+{{O}_{3}}\xrightarrow[{}]{{}}{{H}_{2}}O+C{{l}_{2}}+{{O}_{2}}\] [c] \[3S{{O}_{2}}+{{O}_{3}}\xrightarrow{{}}3S{{O}_{3}}\] [d] \[2Hg+{{O}_{3}}\xrightarrow[{}]{{}}H{{g}_{2}}O+{{O}_{2}}\] Thus,\[S{{O}_{2}}\]does not liberate oxygen with ozone.
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