A) chain isomerism
B) position isomerism
C) chain as well as position isomerism
D) functional isomerism
Correct Answer: C
Solution :
The structures of the given compounds are as \[{{H}_{3}}\overset{3}{\mathop{C}}\,-\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{^{2}C}}}\,-\overset{1}{\mathop{C}}\,{{H}_{3}}\]\[\overset{4}{\mathop{C}}\,{{H}_{3}}\overset{3}{\mathop{C}}\,{{H}_{2}}\overset{2}{\mathop{C}}\,{{H}_{2}}\overset{1}{\mathop{C}}\,{{H}_{2}}Br\] Since in these, the chain of carbon atoms and the position of functional group Ye, Br both are different, they exhibit chain as well as position isomerism.
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