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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2010

  • question_answer
    The volume of a gas at\[21{}^\circ C\]temperature and 768 mm pressure is 1 litre. If the density of the gas is \[1.2\text{ }g\text{ }d{{m}^{-3}}\] at NTP, then its mass will be

    A)  4 g              

    B)  4.22 g

    C)  1.13 g            

    D)  10 g

    Correct Answer: C

    Solution :

     \[\frac{{{p}_{0}}{{V}_{0}}}{{{T}_{0}}}=\frac{pV}{T}\] \[\frac{760\times m}{1.2\times 273}=\frac{768\times 1}{294}\] \[=\frac{768\times 1.2\times 273}{760\times 294}\] \[=1.13g\]


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