RAJASTHAN ­ PET Rajasthan PET Solved Paper-2010

  • question_answer
    A radioactive substance has a half-life of 1 year. The fraction of this material, that would remain after 5 year will be

    A)  \[\frac{1}{32}\]

    B)  \[\frac{7}{5}\]

    C)  \[\frac{1}{2}\]

    D)  \[\frac{4}{5}\]

    Correct Answer: D

    Solution :

     Number of half lives\[n=\frac{5}{1}=5\] Now,     \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}\] \[\Rightarrow \] \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{5}}=\frac{1}{32}\]


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