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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2009

  • question_answer
    If lines\[4x+3y=1,\text{ }y-x=5\]and\[kx+5y=1\]are concurrent, then value of k is

    A)  0              

    B)  1

    C)  3               

    D)  7

    Correct Answer: A

    Solution :

     If given lines are concurrent, then \[\left| \begin{matrix}    4 & 3 & -1  \\    -1 & 1 & -5  \\    k & 5 & -1  \\ \end{matrix} \right|=0\] \[\Rightarrow \] \[4(-1+25)-3(1+5k)-1(-5-k)=0\] \[\Rightarrow \] \[96-3-15k+5+k=0\] \[\Rightarrow \] \[-14k+98=0\] \[\Rightarrow \] \[k=7\]


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